Question

Here is my last one if you don't mind: (2^x^2+1)/(2^x-1)=16

Answer 1

I thought 2^x^2?

Answer 2

I don't know how to write the first part of the exponent. The exponent is x^2 +1

Answer 3

2^x=t

t^2+1=16t-16
now solve it and tell me t's value

Answer 4

Oh wait, I think I don't understand the question.
Is it \(\Large\frac{2^{x^2+1}}{(2^{x-1})}=16\) \[\]

Answer 5

Yes Ishaan that is correct

Answer 6

\[2^{x^2 +1 - x +1} = 2^4\]
\[x^2 -x + 2=4\]

Answer 7

Wow You make that look so easy!!!
Thanks so much

Answer 8

http://www.wolframalpha.com/input/?i=x^2+-x+%2B+2%3D4
At x=2,-1

You're Welcome!

Answer 9

I have one more question, but I'm going to put it in the Question Panel.

Answer 10

\[8^{x ^{2}-2x}=0.5\]