Question

fifty seeds were selected at random from each of 5 bags of seeds,and were kept under standardised conditions favourable to germination.after 20 days,the number of seeds which germinated in each collection were counted and recorded as follows:
bags:1,2,3,4,5
no of seeds germinated:40,48,42,39,41
what is the probability of germination of:
1)more than 40 seeds in a bag?
2)49 seeds in a bag?
3)more than 35 seeds in a bag?

Answer 1

(i) Number of bags in which more than 40 seeds germinated out of 50 seeds is 3.
P(germination of seeds in a bag) = 3= 0.6

Total number of bags is 5.

(ii) Number of bags in which 49 seeds germinated = 0.0 = 0.5 = 1. 5 In all the examples above, you would have noted that the probability of an event can be any fraction from 0 to 1.
P(germination of 49 seeds ) = 5

(iii) Number of bags in which more than 35 seeds germinated = 5.
So, the required probability = ?


(ii) For instance, consider the event that a student weighs 30 kg. Since no student has
this weight, the probability of occurrence of this event is 0. Similarly, the probability
of a student weighing more than 30 kg is 38

Answer 2

Remark for first question.
P(germination of seeds in a bag) = 3/6 which is 0.6

Answer 3

I mean 3/5 not 3/6

Answer 4

k