Question

Prove

Answer 1

suppose log x/y-z=log y/z-x=log z/x-y =k ....
so,log x=k(y-z)
log y=k(z-x)
log z=k(x-y)


x log x=kx(y-z)
y log y=kyu(z-x)
zlog z =kz(x-y)

Answer 2

x log x+ y log y+ z log z=0
log ( x^x y^y z^z )=0
x^x.y^y.z^z=1

Answer 3

how?

Answer 4

what does ur last 3 statements mean?... i'm not making any sense of it...

Answer 5

add the left sides and the right sides

Answer 6

right side will be 0

Answer 7

and log a+log b+log c=log abc

Answer 8

log 1 =0

Answer 9

is it clear ??

Answer 10

wait

Answer 11

sorry there will be no u

Answer 12

its a mistake

Answer 13

how did u conclude that xlogx+ylogy+zlogz=0 ?

Answer 14

x log x+ y log y+z log z=kx(y-z)+ky(z-x)+kz(x-y)

Answer 15

ohhhhh i get it :)

Answer 16

right side
K(xy-xz+yz-xy+xz-zy)
=0

Answer 17

ok

Answer 18

thanks

Answer 19

welcome :)

Answer 20

http://openstudy.com/study#/updates/4f47737de4b00aeb3e3ed004