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For what value of k are the roots of x^2 +kx + 600 = 0 consecutive negative integers?
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49
because ...?
if u find out the divisors of 600,u can see only 24 and 25 are filling the condition
so k will be -((-24)+(-25))
Yes, √600 = approx 24.5 so the consecutive integers must be -24 and -25. Or, x^2 + kx + 600 = (x+24)(x+25) = (x-24)(x-25). For consecutive negative integers, go with the first factoring. k = 49
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yeah
^5
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