Question

Consider the circle of radius 5 centered at (0,0). Find an equation of the line tangent to the circle at the point (3,4).

Answer 1

would it help if i gave multiple choice?

Answer 2

no

Answer 3

equation for the circle is
\[x^2+y^2=5\] taking the derivative gives
\[2x+2yy'=0\]
\[2yy'=-2x\]
\[y'=-\frac{x}{y}\] so slope at
\[(3,4)\] is
\[-\frac{3}{4}\]

Answer 4

actually the equation for the circle is
\[x^2+y^2=5^2\]
\[x^2+y^2=25\] but that does not change the slope

Answer 5

Hey satellite73, how you type the fraction sign?

Answer 6

i dont understand. What is the answer?