Question

graph this problem .

5s – 3 + 1 < 8

Answer 1

Alright, we can simplify the expression down to 5s<10, s<2, through a bit of algebraic manipulation.

s<2 can be represented on a line graph by a hollow circle drawn over the point s=2, and with a line extending in the negative direction.

Answer 2

does a hollow circle look like this ...

Answer 3

Yes. The reason why you draw a hollow circle is because s is LESS THAN two, but not LESS THAN AND EQUAL TO two. Therefore you must specify that s cannot exist at that point.

Answer 4

5s – 3 + 1 < 8
-> 5s < 8 +2
=> s < 10/5 = 2