Question

i need to find 2 distinct numbers where (x+3)/(x^2+9)=1/6

Answer 1

We have\[\frac{x+3}{x^2+9}=\frac{1}{6}\]
cross multiplying we get
\[ 6x+18=x^2+9\]
Bring all the terms to the same side
\[x^2-6x-9=0\]
Can you solve it now using quadratic formula?

Answer 2

i believe so. 6+/-square root 36-4(1)(-9)/2

Answer 3

yeah, correct :D

Answer 4

huzzah

Answer 5

confused though

Answer 6

Why?

Answer 7

what would the answer be? 6/-(36-36)/2?

Answer 8

6+/-(0)/2

Answer 9

\[x =\frac{6\pm\sqrt{36-4 \times (1)\times (-9) }}{2}\]
we get
\[x =\frac{6\pm\sqrt{72 }}{2}\]
72=36*2
so
\[x =\frac{6\pm6\sqrt{2 }}{2}\]
\[x=3\pm 3\sqrt{2}\]
or
\[x=3(1\pm \sqrt{2})\]

Answer 10

my mistake, thanks ash