Question

need help with last problem

Answer 1

this is a pain hold on

Answer 2

exactly haha

Answer 3

\[t(-1)=-4\] for a start, so you want
\[\frac{t(x-1)+4}{x}\]

Answer 4

i wouldn't bother with the denominator under the 4? as a general question?

Answer 5

\[\frac{4}{3(x-1)^3+2}+4\] is the next step

Answer 6

i am just saying that as a number,
\[t(-1)=\frac{4}{3(-1)^2+2}=\frac{4}{-1}=-4\] so the numerator turns in to
\[\frac{4}{3(x-1)^3+2}+4\] we can divide by x last

Answer 7

when you multiply this out and add these up you get
\[\frac{12 x (x^2-3 x+3)}{3 x^3-9 x^2+9 x-1}\]

Answer 8

then divide by x to get
\[\frac{12 (x^2-3 x+3)}{3 x^3-9 x^2+9 x-1}\]

Answer 9

who thought this up?????

Answer 10

its online math hw for my college pre-calc class haha.

Answer 11

glad it is you and not me.
enjoy

Answer 12

thanks though haha, the answers worked. Thanks Satellite