Question

i got the fraction part right but i cant figure out how to get the variables: 4m^3/3m^2n multiplied by 9n^2/30m^2n^2 = 2/5

Answer 1

\[\Large \frac{x^a}{x^b} \to x^{a-b}\]

Answer 2

\[\Large x^a \times x^b \to x^{a +b}\]

Answer 3

m=1
n=1

Answer 4

I'm not sure though, because it's a weird answer, let me check over my work.. it's a bit messy.

Answer 5

how would that work if the variables cant be divided by each other?

Answer 6

\[(4m^{3}/3m^{2}n) \times (9n^{2}/30m^{2}n^{2}) = 2/5\]

Answer 7

It makes sense though... use cross cancellation, that's the method I used:

you would get 2/5mn=2/5

so basically you know that:

mn=1

therefor m and n must both be 1.

If you plug in one as the variables... it works out!

so the answer is:

m=1
n=1

Answer 8

im still confused. would you cancel them out going across or up and down?

Answer 9

You can cross cancel things every way except across.

Answer 10

that means things that are diagonal can cross out.

Answer 11

can you draw out how you did that?

Answer 12

was the question this?