find slope of tangent line y=f(x)=xsquared + 1 at (2,5) given f'(x)=2x

Question

cwrw238 · Answer

the slope = 2x 
at (2,5) x = 2 so slope of tangent = 2(2) = 4

2bornot2b · Answer

So your question is to find the slope of the equation$f(x)=x^2+1$ at (2,5) given f'(x)=2x

2bornot2b · Answer

joycelefebvre are you new to OS?

anonymous · Answer

yes could you show me your work on that please i'm studying for praxis 0061 my study guied doesnt show work its horrible tu

2bornot2b · Answer

OK let me help you

2bornot2b · Answer

Given any function, the derivative of the function is the equation to the slope of the given equation--------did you know that?

anonymous · Answer

kinda I took calc in college in 93 and its not coming back

2bornot2b · Answer

OK, then I am trying to refresh that. 
Suppose you have a function y=f(x), so the function y=f'(x) is the equation of the tangent of the function y=f(x)

2bornot2b · Answer

OK?

2bornot2b · Answer

So your given function is $f(x)=x^2+1$ and $f'(x)=2x$

2bornot2b · Answer

Now as I told you earlier, $f'(x)$ should be the equation of the tangent at any point

2bornot2b · Answer

Your question asks you to find the equation of the tangent at (2,5) so just put x=2 in the equation to tangent i.e. 2x2=4.
So the answer is 4
Got it?

anonymous · Answer

omg I was trying to do y2-y1/x2-x1

2bornot2b · Answer

This is actually a theorem.. If you just remember it you don't have to find the tangent that way.......... I mean the way you are trying using the formula $\frac {y2-y1}{x2-x1}$

2bornot2b · Answer

The theorem is, 
Let y=f(x) be a given equation, to find the equation to the tangent at any point is y=f'(x) where f'(x) is the derivative of the function f(x)

2bornot2b · Answer

Is that clear, any problem?

anonymous · Answer

tu i couldn't find the praxis study guied for 0061 so i got the cliff notes  and its all text no examples

2bornot2b · Answer

Did you know you can chat with other users in the maths group?

2bornot2b · Answer

In that way you can get help from experts?

2bornot2b · Answer

Come join me in the chat room (do you know how?)

anonymous · Answer

no

2bornot2b · Answer

Do you see those green boxes below

anonymous · Answer

your 31

2bornot2b · Answer

See there I have posted you a chat message

2bornot2b · Answer

Yes, I am 31, thats my level.

2bornot2b · Answer

But chatting is a different thing

anonymous · Answer

my lap top keeps telling me i cant run this script

2bornot2b · Answer

OH, I see, what operating system are you using?