Given: DA, TO, and CG are all medians of Triangle DOG. Find the measure of angle DGC Angle DAG Angle DOG Angle DGC Angle DAO Angle OCG Please help. I have no idea where to even start.
Angle DGO is supplementary to 150, so DGO is 30. Angle ODG is 40+20 = 60. Angle DOG then is 180 - (m DGO + m ODG) = 180 - 30 - 60 = 90 that may make for a start
From there, it looks like you can find all of the angles through triangle angle sums and given information
How would I find angle DAG?
looking at triangle DAG, we know angle DGA is 30 and angle ADG is 20. So, DGA + ADG + DAG = 180 => 20 + 30 + DAG = 180
ooh
I'm stuck on finding the measure of OCG, may you help please?
Wait, i think i might have it. Is it 65?
Looking at triangle OGC, we figured out that angle COG was 90. CGO is half of DGO, which was 30. 1/2 (30) = 15. 15 + 90 + m OCG = 180
no wait, not 65, i mean 75
That would be correct. :)
:)
To find y, would I add 4y +2 + 44 = 180?
Damn you were a good helper
That property only applied to the angles of a triangle. Basically, the centroid divides all three of those lines in a ratio of 2:1. Looking at CG, 4y + 2 = 1/2 of 44 (since 44 would be twice the length of "4y + 2")
So, 4y + 2 = 22; for y 4y = 20 y = 5
you there?
Now I am. (kinda, am cleaning room lol)
hELP
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please help
oh my god thank you so much for being here... I just got this assignment back and I got to redo it. I am stuck on this problem again. I can't find how to separate angle DOA. It equals 90, but I don't know which angle equals which.
It splits into 65 and 25, but I forgot how I got that.
angle DOT and TOA
That's the other question with the same problem.
okay.. sorry, i just gotta take a look at the problem again. im not remembering the process, so i gotta work it out again. :P
No problem. In fact, thank you so much for taking your time :)
Finals are tomorrow. I'm hoping I can get at least a B.
man, im not seeing how you get those angles... i found most other angles except those two and some interior angles in the center
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