Question

solve using the principle of zero (7c+3)(4c-12)=0

Answer 1

I just don't understand how to do this one since it's not as easy as the last one I asked about and I wanted to know where I messed up

Answer 2

(7c+3)(4c-12)=0
------------------------------
(7c+3)=0

7c+3=0

7c=-3

7c/7=-3/7

c=-3/7

OR

(4c-12)=0

(4(c)+4(-3))=0

(4(c-3))=0

(c-3)=0

c-3=0

c=3
=================
c= -3/7 , 3

Answer 3

oh thank you, that makes sense. I really appreciate the help!!