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Mathematics 6 Online
OpenStudy (anonymous):

Please see link: http://s1084.photobucket.com/albums/j409/QRAWarrior/?action=view¤t=MATA30Y-Attempt.png

OpenStudy (anonymous):

OpenStudy (anonymous):

^ direct link above

OpenStudy (anonymous):

I showed the right hand side, but I don't know how I would show left. The minimum value that sin^2(x) can be is 0, but that just messes things up.

OpenStudy (turingtest):

The only problem here is that you plugged in a value for x in the integral before you evaluated it leave x in the integral and you can show that\[\int xdx\]is in the range you are looking for. Since sin^2 can only make the value smaller, the integral will always be in that range

OpenStudy (turingtest):

also sin^2 cannot be zero because the interval is from pi/4 to pi/2, and sin>0 in that range

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