Question

Ok really need help on this one!

Answer 1

multiply d^2 to both sides

Answer 2

that gets rid of the d^2 from both sides. Then divide d^2 to both the bottom and top side of the left side

Answer 3

I mean it gets rid of d^2 from the left side

Answer 4

and on the right side it becomes -1?

Answer 5

lets say n1= messy side of the left and n=2 for all the messy things from the right side

n1/d^2 = n2/(40 - d^2)
n1 = n2* d^2/ (40 - d^2) you get this from multiplying d^2 to both sides

n1 = n2* d^2/ (40 - d^2) divide n2 to both sides
n1/n2 = d^2/ (40 - d^2)

n1/n2 = 1/ (40/d^2 - 1) you get this from divide d^2 to both the bottom and top side of the left side

(40/d^2 - 1) = 1/n1/n2
(40/n2/n1 + 1) = d^2
square root both sides and you get the answer

like i said before n1 and n2 are the messy things from the left and right respectively

Answer 6

The last part might be confusing let me know if you need more help.

Answer 7

it got confusing midway through lol cause of all the letters and numbers..do you think you could draw the steps instead?

Answer 8

One other easy way is to inspect and cancel out the common values on both sides. Everything cancels out and leaves the following simplified format:

-5/d^2 =-2/[40 -d^2]
=> -200 + 5*d^2 = -2*d^2
=> 7*d^2 = 200
hence d= sqrt(200/7)

Answer 9

is this correct?

Answer 10

this gives as d= 5.3452

Answer 11

can you check your calculations again because it is 0.40

Answer 12

(the part in the denominator)

Answer 13

chemwile is correct assuming his simplification of my n1 and n2 are correct

Answer 14

and i calculated with .4 and got d=0.53..hopefully this is correct :)

Answer 15

and thanks a bunch to chemwile for the simpler version!! it really helped a lot!

Answer 16

Yes you are right. I had used 40 instead of .4. Your answer is correct.

Answer 17

cool thank you.