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2NaN3 > 2Na + 3N2 a. 56.0 grams b. 42.0 grams c. 28.0 grams d. 18.7 grams
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The question is nonsensical I'm afraid. \[2NaN _{3}\rightarrow2Na+3N _{2}\] With that alone you are able to find out how many moles of one or the other is produced. So for every 2 moles of Sodium Trinitride you get 2 moles of Sodium and 3 moles of Nitrogen gas. Using that information and the molar masses found on the periodic table, you can find out how many grams of one substance you would get if you are given a certain amount of grams of another substance.
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