Ask
your own question, for FREE!
Mathematics
19 Online
Complicated Derivative Problem:
Still Need Help?
Join the QuestionCove community and study together with friends!
h(x) = f^3(g(x)) h'(x) = 3f^2(g(x)) * g'(x) by the chain rule
close
h(x) = (f(g(x)))^3 h'(x) = 3(f(g(x)))^2 * f'(g(x)) * g'(x)
yup okay I got that far
Still Need Help?
Join the QuestionCove community and study together with friends!
wait...oh I see i made an error when using the chain rule
h'(1) = 3(f(g(1)))^2 * f'(g(1)) * g'(1) h'(1) = 3(f(3))^2 * f'(3) * 3 h'(1) = 3(2)^2 * 5 * 3
h'(1) = 180 by chance?
thats strange, I got 300, let me check my work :O
isnt g'(1)=5?
Still Need Help?
Join the QuestionCove community and study together with friends!
instead of 3?
yeah, trying to flip back and forth between windows tends to mess me up alot more than usual
lol XD sorry about that
concept is good tho :)
Thanks for the help!
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
thereneelg:
Okay....I'm doing a group solo for choir. Auditions are Tuesday (?), Any tips on
Arizona:
my Rolling stone airpods won't connect and I got them about a year ago is there t
Arizona:
can someone check out my essay i'm doing in my senior English class about the McD
IcedShots:
I was wondering, is there anybody on here around my age? Im turning 15 on December 1 ud83dude0a.
thatonenerd:
Use Hvap of water = 40.7 kJ/mol, c of water = 4.184 J/g.u00b0C, and molar mass of HO = 18.
letrasbonitasz:
Typography plays an important role in digital communication. Different font styles can make social media profiles, usernames, messages, and creative designs
Bounty:
tested love: im so over love it acquires patience i don't have trials an tribulations yet my souls the only one taken i give 90 you give 10 you say that you
SaltySuga:
is it possible to tell how deep a cut is by an open wound? like would i be able t
1 day ago
0 Replies
0 Medals
1 day ago
3 Replies
0 Medals
2 days ago
1 Reply
0 Medals
1 day ago
3 Replies
0 Medals
3 days ago
5 Replies
0 Medals
5 days ago
3 Replies
1 Medal
3 days ago
7 Replies
2 Medals
5 days ago
5 Replies
1 Medal