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OpenStudy (anonymous):
Differentiate each of the following functions with respect to x.
(i) \[e^{x^3}\]
(ii)\[{-1\over2}x^{(1/2)^2}\]
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OpenStudy (anonymous):
Sorry, the (II) has no -1/2 infront
OpenStudy (anonymous):
\[\left( e ^{x ^{3}} \right)\prime ===> 3x ^{2}e ^{x ^{3}}\]
OpenStudy (anonymous):
Yes, but why?
OpenStudy (anonymous):
e^(x^3) ->e^(x^3) * (x^3)' = 3x^2 * e^(x^3)
OpenStudy (anonymous):
the derivative of e^x is itself times the derivative of x
in this case x is x^3
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OpenStudy (anonymous):
and derivative of X^3 is 3*x^2
OpenStudy (anonymous):
When you have, e^(something), the derivative is e^(something) multiplied by the derivative of something
OpenStudy (anonymous):
Ok, I understand. How about the second one?
OpenStudy (anonymous):
\[x^{(-1/2)^2}\]
OpenStudy (anonymous):
is that x^((-1/2)^2)
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OpenStudy (anonymous):
tell me if im wrong but is that just -1/2 x^1/4 to simplify? then you just find that derivative
OpenStudy (anonymous):
sorry \[e^{(-1/2)x^2}\]
OpenStudy (anonymous):
e^n derivative is e^n * n'
where n = (-1/2)*x^2
n'= -x
OpenStudy (anonymous):
\[(e ^{(-1/2)x ^{2}})\prime ===> e ^{(-1/2)x ^{2}}(-x)\]
OpenStudy (anonymous):
Oh. Ok
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OpenStudy (anonymous):
derivative of e^(_x)=-e^(-x)
ans=(-1/2)e^(-1/2)x^2{-x}=(1/2)e^(-1/2)x^2
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