Question

\[\int\limits_{-3}^{9}e^{xIn3}dx\]

Answer 1

Let
u=xln3

dx=(du)/(ln3)

(e^(u))/(ln3)

(e^(xln3))/(ln3)+C

(e^((9)ln3))/(ln3)-[(e^((-3)ln3))/(ln3)]

531440/27ln3

Answer 2

The inside if just 3^x even before integration if you simplify it

Answer 3

The answer is \[{1 \over In3}(3^9-{1\over27}) ~~~~~ In~~this~~form\]

Answer 4

Thanks Sam

Answer 5

[(3^x/ln3)-(3^x/ln3)] simplify out 1/ln3
1/ln3 [(3^x)-(3^x)]
replace the first x with 9 and the second with -2

Answer 6

integral of 3^x = 3^x/ln3

Answer 7

Thanks. I understand :)