Question

Add or subtract the rational expressions, as indicated, and simplify the answer.

Answer 1

\[\frac{x^2-1}{x-2}-\frac{x-1}{x+1}\]

Answer 2

your only choice for the denominator is the product of these two so it will be
\[(x-2)(x+1)\] and your work will be in the numerator
start with
\[\frac{(x^2-1)(x+1)-(x-1)(x-2)}{(x-2)(x+1)}\] then multiply out in the numerator, combine like terms, etc.
do not look to cancel, it is very unlikely

Answer 3

Oh i see well thanks. I have one more if you would like to help me solve it.

Answer 4

sure
when all is said and done your numerator should be
\[x^3+2 x-3\] or if you want to factor
\[(x-1) (x^2+x+3)\] so you will get
\[\frac{x^3+2x-3}{(x-2)(x+1)}\]

Answer 5

So the final answer is the bottom one?

Answer 6

yes, unless you want to write the numerator in fatored form

Answer 7

no it just says to write it in simplified form.

Answer 8

One sec i will write the other problem.

Answer 9

\[\frac{y+2}{y-2}+\frac{y-6}{y+4}+\frac{4}{y^2+2y-8}\]

Answer 10

if you are lucky
\[y^2+2y-8\] is the product of
\[(x-2)(x+4)\] and it is, so you can use that one as your least common denominator

Answer 11

\[\frac{y+2}{y-2}+\frac{y-6}{y+4}+\frac{4}{y^2+2y-8}\]
\[\frac{y+2}{y-2}\times \frac{y+4}{y+4}+\frac{y-6}{y+4}\times \frac{y-2}{y-2}+\frac{4}{y^2+2y-8}\]

Answer 12

now your denominator is the same for each fraction, namely
\[(y+4)(y-2)\] or
\[y^2+2y-8\] and again all the work is in the numerator. you have to multiply out, combine like terms etc.

Answer 13

\[(y+2)(y+4)+(y-6)(y-2)+4\] is your numerator.
when you do the algebra you should get
\[2 y^2-2 y+24\] for the numerator

Answer 14

Thanks man your a genius lol.

Answer 15

Just making sure the final answer is the bottom one?

Answer 16

your only choice for the denominator is the product of these two so it will be
(x−2)(x+1)
and your work will be in the numerator
start with
(x2−1)(x+1)−(x−1)(x−2)(x−2)(x+1)
then multiply out in the numerator, combine like terms, etc.
do not look to cancel, it is very unlikely
22 minutes agoReport Abuse
11
alexsu22 This is the asker
Oh i see well thanks. I have one more if you would like to help me solve it.
21 minutes agoReport Abuse
100
satellite73 1 Good Answer
sure
when all is said and done your numerator should be
x3+2x−3
or if you want to factor
(x−1)(x2+x+3)
so you will get
x3+2x−3(x−2)(x+1)
20 minutes agoReport Abuse
11
alexsu22 This is the asker
So the final answer is the bottom one?
19 minutes agoReport Abuse
100
satellite73 1 Good Answer
yes, unless you want to write the numerator in fatored form
18 minutes agoReport Abuse
11
alexsu22 This is the asker
no it just says to write it in simplified form.
18 minutes agoReport Abuse
11
alexsu22 This is the asker
One sec i will write the other problem.
16 minutes agoReport Abuse
11
alexsu22 This is the asker
y+2y−2+y−6y+4+4y2+2y−8
12 minutes agoReport Abuse
100
satellite73 1 Good Answer
if you are lucky
y2+2y−8
is the product of
(x−2)(x+4)
and it is, so you can use that one as your least common denominator
11 minutes agoReport Abuse
100
satellite73 1 Good Answer

y+2y−2+y−6y+4+4y2+2y−8

y+2y−2×y+4y+4+y−6y+4×y−2y−2+4y2+2y−8

10 minutes agoReport Abuse
100
satellite73 1 Good Answer
now your denominator is the same for each fraction, namely
(y+4)(y−2)
or
y2+2y−8
and again all the work is in the numerator. you have to multiply out, combine like terms etc.
9 minutes agoReport Abuse
100
satellite73 1 Good Answer

(y+2)(y+4)+(y−6)(y−2)+4
is your numerator.
when you do the algebra you should get
2y2−2y+24
for the numerator
8 minutes agoReport Abuse
11
alexsu22 This is the asker
Thanks man your a genius lol.
4 minutes agoReport Abuse
11
alexsu22 This is the asker
Just making sure the final answer is the bottom one?
3 minutes agoReport Abuse
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Answer 17

i know im a genius alexsu :) U R TOO NO WORRIES K

Answer 18

i am genius

Answer 19

Everybody is genius except me :/