Question

Does anyone know how to do imaginary numbers? I have one problem. that's a doozy

Answer 1

doozy ? seriously . just give it to me im a genious! ok :)

Answer 2

post it

Answer 3

u know i aint got all day

Answer 4

i kr

Answer 5

HURRY!!!

Answer 6

i have university soon

Answer 7

ya know its advance

Answer 8

me too

Answer 9

\[ \sqrt{3} \times \sqrt{-128}\]

Answer 10

lol

Answer 11

guess ill be leaving if u dont give me the genius question some people are snobs

Answer 12

i didnt get any younger u know

Answer 13

please show steps. I have came up with three different answers

Answer 14

post them

Answer 15

@Tia1977 give me a medal first

Answer 16

me 2

Answer 17

then solve it as piece of cake

Answer 18

would u like some cake it comes with genius ya know

Answer 19

ok the answer is 48 U WELCOME!!1

Answer 20

Thats impossible.<-- my answer

Answer 21

well thx forr the medal, guess ill be leaving now, college ya know

Answer 22

steps please!

Answer 23

its 48

Answer 24

first off,
\[128=2^7\]

Answer 25

sorry i dont do steps i do it all in myhead thats y im a genius

Answer 26

see ya

Answer 27

woudnt wanna be ya

Answer 28

hahahaha that rhymes

Answer 29

ok

Answer 30

and therefore
\[\sqrt{-128}=\sqrt{2^7\times (-1)}=\sqrt{2^7}\times \sqrt{-1}=\sqrt{2^6}\times \sqrt{2}\times \sqrt{-1}=8\sqrt{2}i\]

Answer 31

therefore
\[\sqrt{3}\times 8\sqrt{2}i=8\sqrt{6}i\]

Answer 32

ok. I got

Answer 33

\[\sqrt{3} \pm \sqrt{2}\]

Answer 34

not sure what is wrong