So i got this equation, i want to solve for X, how do i do it: (I-D)X=E
(I-D)X=E divide both sides by (I-D) X=E/(I-D) or in a slightly more pretty format: \[X=\frac{E}{I-D}\]
okay but this isnt a normal equation its a matrix equation
you see i need to isolate that x, which is a output matrix
\[X=E\times(I-D)^{-1}\]
would be the normal matrix notation, if I remember correctly.
okay thanks
not quite
I havent worked in matricies in a long time, so go for it amistre.
(I-D)X = E we have to multiply by the inverse on the LEFT of each term (I-D)^-1 (I-D)X = (I-D)^-1 E X = (I-D)^-1 E
B^-1 A not = A B^-1 in general
yeah, i vaguely remember that now, lol
:)
nice job smart guy
i learn from my mistakes; and i have made alooot of mistakes ;)
okay man heres your medal
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