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OpenStudy (anonymous):
So i got this equation, i want to solve for X, how do i do it:
(I-D)X=E
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OpenStudy (agreene):
(I-D)X=E divide both sides by (I-D)
X=E/(I-D) or in a slightly more pretty format:
\[X=\frac{E}{I-D}\]
OpenStudy (anonymous):
okay but this isnt a normal equation its a matrix equation
OpenStudy (anonymous):
you see i need to isolate that x, which is a output matrix
OpenStudy (agreene):
\[X=E\times(I-D)^{-1}\]
OpenStudy (agreene):
would be the normal matrix notation, if I remember correctly.
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OpenStudy (anonymous):
okay thanks
OpenStudy (amistre64):
not quite
OpenStudy (agreene):
I havent worked in matricies in a long time, so go for it amistre.
OpenStudy (amistre64):
(I-D)X = E
we have to multiply by the inverse on the LEFT of each term
(I-D)^-1 (I-D)X = (I-D)^-1 E
X = (I-D)^-1 E
OpenStudy (amistre64):
B^-1 A not = A B^-1 in general
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OpenStudy (agreene):
yeah, i vaguely remember that now, lol
OpenStudy (amistre64):
:)
OpenStudy (anonymous):
nice job smart guy
OpenStudy (amistre64):
i learn from my mistakes; and i have made alooot of mistakes ;)
OpenStudy (anonymous):
okay man heres your medal
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