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Mathematics 25 Online
OpenStudy (anonymous):

So i got this equation, i want to solve for X, how do i do it: (I-D)X=E

OpenStudy (agreene):

(I-D)X=E divide both sides by (I-D) X=E/(I-D) or in a slightly more pretty format: \[X=\frac{E}{I-D}\]

OpenStudy (anonymous):

okay but this isnt a normal equation its a matrix equation

OpenStudy (anonymous):

you see i need to isolate that x, which is a output matrix

OpenStudy (agreene):

\[X=E\times(I-D)^{-1}\]

OpenStudy (agreene):

would be the normal matrix notation, if I remember correctly.

OpenStudy (anonymous):

okay thanks

OpenStudy (amistre64):

not quite

OpenStudy (agreene):

I havent worked in matricies in a long time, so go for it amistre.

OpenStudy (amistre64):

(I-D)X = E we have to multiply by the inverse on the LEFT of each term (I-D)^-1 (I-D)X = (I-D)^-1 E X = (I-D)^-1 E

OpenStudy (amistre64):

B^-1 A not = A B^-1 in general

OpenStudy (agreene):

yeah, i vaguely remember that now, lol

OpenStudy (amistre64):

:)

OpenStudy (anonymous):

nice job smart guy

OpenStudy (amistre64):

i learn from my mistakes; and i have made alooot of mistakes ;)

OpenStudy (anonymous):

okay man heres your medal

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