Question

what is log(8)12

Answer 1

use change of base... say base e logs

\[\log_{8} 12 = (\log_{e} 12)/(\log_{e} 8)\]

should be around 1.5 or 1.6

Answer 2

thank u

Answer 3

ummm 8^1 = 8, 8^2 = 64.... 12 is between 1 and 64 so its about 1.1