Ask your own question, for FREE!
Physics 13 Online
OpenStudy (anonymous):

HELP PLEASE WITH MOMENTUM !

OpenStudy (anonymous):

A 200 Kg car is traveling at 5 meters per second. momentum = 10000 A constant force of 500 n is applied for 5 secs to the same car in the above question by its engine. What is the impulse applied to the car by the force of its engine? impulse = 2500 What is the new momentum? = 12500 What is its new speed? What is the increase in its speed? What impulse is required to stop the car? What is the force required if we wanted to stop the car in 5 seconds?

OpenStudy (anonymous):

Impulse is defined as\[I = \int Fdt\]We know from Newton's Second Law that\[F = {dp \over dt}\]Therefore, \[I = \int\limits {dp \over dt} dt\]\[I = \Delta p\]Since mass remains constant\[\Delta p = m \Delta v = m(v_f - v_i)\]Therefore, \[F \Delta t = m(v_f - v_i)\] This should get you started.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
3 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
3 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!