a student needs 200 mL of 1M NaOH for an experiment. The stockroom has 12M NaOH only. How can the student prepare 1M NaOH from the 12M available?

Question

anonymous · Answer

M1V1=M2V2
So u are given the M of the beginning solution and the required amount and molarity of the final. So fill in the blanks:
M1= 12M
V1= x
M2=1M
V2=200 mL

(12M)x=(1M)(200mL)

After u solve for x, u subtract that value from 200 mL and that is how much water u add to properly dilute it

anonymous · Answer

Ok! I was right, I did all of the steps but I made a miscalculation. Thank you!