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Mathematics 19 Online
OpenStudy (anonymous):

Say I have a three digit combination lock. What is the minimum number of trials I need on the combination to ensure that I get the correct combination? Hint.. answer is not 10^3 ...

OpenStudy (kinggeorge):

If I type in these numbers; 0123456789, will it count as trying all of 012, 123, 234, 345, 456, 567, 678, and 789?

OpenStudy (kinggeorge):

Or only 012, 345, 678, 9?

OpenStudy (anonymous):

012, 345, 678

OpenStudy (kinggeorge):

Are there any other restrictions? Otherwise, I don't see how it could be anything but \(10^3\).

OpenStudy (campbell_st):

well there are 10^3 possible combinations... so you could take 10^3 -1 attempts before you get the successful combination

OpenStudy (campbell_st):

that is assuming the correct combination is the last 1 entered

OpenStudy (campbell_st):

then its 9^3 - 1 since only 9 digits

OpenStudy (campbell_st):

so 728 trials may be needed

OpenStudy (campbell_st):

minimum is 1 trial as you get it 1st go

OpenStudy (anonymous):

Okk .. I would elaborate the question ... I have a three digit combination lock with each digit having 10 possibilities. Once the correct combination is entered the lock opens automatically. How will I optimize my search so as to ensure that I get the combination in the mimimum number of trials. Whst is the minimum number of trials? None of the answers given so far are correct

OpenStudy (campbell_st):

well you gave us 9 digits 0 to 8

OpenStudy (anonymous):

Is this really possible? I mean is there a algorithm for this system which could be faster than the brute force algorithm.

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