Question

Also, solve for x: log(7x+1)-log(x^2+13)=0

I honestly cannot solve this.

Answer 1

x=4 or 3

Answer 2

log(x^2+13)= log (7x+1)
x^2+13 = 7x+1
x² - 7x + 12 = 0
=> x = 3 , x = 4

Answer 3

take the exponential to get rid of the logs

then 7x + 1 = x^2 + 13

(x -3)(x-4) = 0 x = 3,4

Answer 4

Oooh see I thought it was log (7x+1)/(x^2+13)

Thanks!!