Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

for constants a ,b, n, R, Van der waals equation relates the pressure P to the volume V of a fixed quantity of a gas at constant temperature T:

OpenStudy (anonymous):

\[(P + (n^2a)/V^2) (V -nb) = nRT\] Find the rate of change of volume with pressure dV/dP

OpenStudy (anonymous):

So you just need to take a derivative with respect to P right? The only variables that depend on P are P and V right? So differentiate: \[\frac{d}{dV}(P+\frac{n^2a}{V^2})(V-nb)=\frac{d}{dV}nRT\] First look at the right side, since n,R, and T are constants then the derivative with respect to V of that product is zero. For the left side, we have a term of n^2a/V^2 and V-nb, so we need a PRODUCT RULE: \[\frac{d}{dx}f(x)g(x)=f'(x)g(x)+f(x)g'(x) \] So: \[\implies 0 = \frac{d}{dV}(P+\frac{n^2 a}{V^2})(V-nb)+(P+\frac{n^2 a}{V^2}) \frac{d}{dV}(V-nb)=\] \[(\frac{dP}{dV}-\frac{2 n^2 a}{V^3})(V-nb)+(P+\frac{n^2 a}{V^2})(1)=0 \implies \frac{dP}{dV}=\frac{P+\frac{n^2 a}{V^2}}{nb-V}+\frac{2n^2 a}{V^3}\] The way I see it.

OpenStudy (anonymous):

thank you that makes so much more sense then when my teachers was on this topic.

OpenStudy (anonymous):

You're welcome :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
6 hours ago 3 Replies 0 Medals
Arriyanalol: help
5 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
8 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
8 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!