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Mathematics 19 Online
OpenStudy (anonymous):

find the limits graphically and numerically lim (2x+3) x->4 help please I don't understand how the professor got the answer: lim(2x+3)=11 x->4 thank you!

OpenStudy (anonymous):

the function is a line ...so no discontinuities, no gaps, no cusps, no jumps... All you have to do is to plug in 4 for x . 2(4) +3 = 11

OpenStudy (anonymous):

you just plug in the 4 into the equation

OpenStudy (anonymous):

yeah I should have looked at the math first lol, but yes the graph is continous

OpenStudy (anonymous):

which makes sense because it is a line and that function has a domain of all real numbers

OpenStudy (anonymous):

so the vertical asymptote is approximating? to 4? and to graph numerically? would be a number closed to 11?

OpenStudy (anonymous):

1. There is no vertical asymptote. There is only a verticle asymptote when the answer is plus or negative infinity. 2. To graph numerically? You either graph it or do it numerically 3. The answer is 11, that is the limit

OpenStudy (anonymous):

thx!

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