Question

A partical moves in a straight line with the velocity of v(t)=t^2.How far does the partical move between times t=1 and t=2?
please help >~<

Answer 1

\[v(t)=t ^{2}\]
\[dx/dt=t ^{2}\]
\[dx=t ^{2}dt\]
\[x=\int\limits_{1}^{2} t ^{2}dt\]
Now, do it.
Hey watsgood, v'(t) is equal to acceleration, not distance :)

Answer 2

ty ^^

Answer 3

ino its accelertion but it says we need the distance

Answer 4

agh im confused now

Answer 5

x is the distance. Find the result of that integration. You will get the distance. Should I integrate it for you?