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Mathematics 13 Online
OpenStudy (anonymous):

A partical moves in a straight line with the velocity of v(t)=t^2.How far does the partical move between times t=1 and t=2? please help >~<

OpenStudy (mani_jha):

\[v(t)=t ^{2}\] \[dx/dt=t ^{2}\] \[dx=t ^{2}dt\] \[x=\int\limits_{1}^{2} t ^{2}dt\] Now, do it. Hey watsgood, v'(t) is equal to acceleration, not distance :)

OpenStudy (anonymous):

ty ^^

OpenStudy (anonymous):

ino its accelertion but it says we need the distance

OpenStudy (anonymous):

agh im confused now

OpenStudy (mani_jha):

x is the distance. Find the result of that integration. You will get the distance. Should I integrate it for you?

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