Question

Need to find f(x)=x^cosx

Answer 1

Okay. I'm pretty sure we're missing an important bit of information, i.e., the question itself.

Answer 2

I found it!! f(x)=x^cosx

Answer 3

Formula:
d/dx sinh x=cosh x

Answer 4

look under the couch

Answer 5

Either I'm missing something, or no question is being asked.

Answer 6

I don't understand this question either :(

Answer 7

are you trying to find the derivative??

Answer 8

Wow @satellite73 what makes you think you can go and be helpful?

Answer 9

you don't "find a function"
maybe you find the domain or range?
derivative or integral? graph?

Answer 10

Yes, the question is find the derivative using the method:
d/dx sinh x=cosh

Answer 11

@badreferences Satellite thinks that because it is true.

Answer 12

\[f(x)=x^{\cos(x)}=e^{\cos(x)\ln(x)}\]

Answer 13

take the derivative using the chain rule and the product rule, get
\[e^{\cos(x)\ln(x)}\times (-\sin(x)\ln(x)+\frac{\cos(x)}{x})\]

Answer 14

awesome! thank you so much!

Answer 15

yw

Answer 16

satellite will u help me?

Answer 17

Okay this is the last one under the same conditions:

\[y= x(x^2+1)\div \sqrt{x+1}\]

Answer 18

\[\frac{x^3+x}{\sqrt{x+1}}\]

Answer 19

\[\frac{\sqrt{x+1}(3x^2+1)-(x^3+x)(.5(\sqrt{x+1})^{-.5}}{x+1}\]

Answer 20

(x-1) squared on the denominator, right?

Answer 21

The original denominator was sqrt(x+1). When you square that, you get x+1

Answer 22

Okay I see, cool...