Question

How do you find the distance between -15 and 12 on a number line.

1 : 27
2: -27
3: 3
4: -3

Answer 1

1: 27

Answer 2

distance is always nonnegative

Answer 3

12 - (-15) = 27

Answer 4

as rulnick says, distance is never negative
so
gap between -15 and 0 is 15
gap between 0 and 12 is 12
so distance between -15 and 12 is 15 + 12 = 27

Answer 5

:\ I posted the wrong question i was helping a friend .. im so sorry :( I ment to post

Find the distance between points at (-2, 9) and (8, 33).

1: 32
2: 26
3: 28
4: 35

Answer 6

Im really sorry about that if you could plz help me I dont under stand how to find the distance between the points

Answer 7

dist from (x1,y1) to (x2,y2) is sqrt( (x2-x1)^2 + (y2-y1)^2 ).

Answer 8

so you need sqrt(24^2+10^2).

Answer 9

... it's 26.

Answer 10

Where did you get the 24^2 + 10^2 from?

Answer 11

y2 - y1
x2 - x1
(subtract the coordinates individually)

Answer 12

|a-b|

Answer 13

or .... get one of the number to zero :)

Answer 14

-15 and 12
+15 +15
----------
0 and 27

whats the distance from 0 to 27?

Answer 15

(-2, 9) and (8, 33)

get one point to the (0,0)

(-2, 9) and (8, 33)
+2 -9 +2-9
----------------
(0,0) (10,24)

Answer 16

the distance then is just the hypotenuse of the right triange of sides; 10 and 24

Answer 17

\[d=\sqrt{10^2+24^2}\]

Answer 18

OH its like algebra ok i under stand it now

Answer 19

THank you just had to get that light to go off xD

Answer 20

yep