g(s)=(s+4)/((s^2)+1s+14)
find g'(s).
quotient rule right?

Question

g(s)=(s+4)/((s^2)+1s+14)
find g'(s).
quotient rule right?

accessdenied · Answer

yeah, you could use quotient rule

anonymous · Answer

yep

anonymous · Answer

can someone get me started please

anonymous · Answer

dont want the answer. just get me started.

accessdenied · Answer

$$ F_1 = s + 4, F_2 = s^2 + s + 14 $$
$$ \frac{F_1' F_2 - F_1 F_2 '}{F_2^2} $$

anonymous · Answer

do u think all of these rules will be given to me on a test or should i memorize them?

accessdenied · Answer

i doubt they'd be given, it'd be better to memorize them.  usually (at least when i was learning the rules), they start to become more second nature as you do more problems.

anonymous · Answer

true. too much to store in the brain though. haha

accessdenied · Answer

its technically possible to use product rule on those quotients of functions if you redefine it in the form f/g = (f)(g)^(-1) , that could possibly help in minimizing the formulas you need to remember... lol

anonymous · Answer

ok im getting the wrong final answer for this. can you help me out here?

accessdenied · Answer

what are you getting for your answer?

anonymous · Answer

-s^2 - 8s + 10 / (s^2 + s + 14)^2

anonymous · Answer

maybe im making a syntax error

accessdenied · Answer

I'm gonna use f(s) = s+4 and g(s) = s^2 + s + 14 instead of my previous F1 and F2 for easier reading.

Given those f(s) and g(s), their derivatives...
f'(s) = 1
g'(s) = 2s + 1

f'(s)g(s) - f(s)g'(s)
--------------
          gIs)^2

maybe that'd be easier to understand

accessdenied · Answer

oh, hmm, i get that too

accessdenied · Answer

maybe it would like you to multiply out the denominator

anonymous · Answer

i made a syntax error. its an old school hw website.

accessdenied · Answer

ah, i see