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Is y=x^2 a function? Is the inverse of y=x^2 a function? Justify your answer
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Do you know the inverse of y=x^2 first of all?
Is it x = y?
swap the x and y in f(x) to get f^-1(x) x=y^2, solve for y
\[y= \pm \sqrt{x}\]
so you're going to have 2 y values for each x-value that is not 0
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is that a function?
In a function, each member of the domain corresponds to at most 1 member of the range
No it's not.
right, and is y=x^2 a function?
No, because it's a parabola?
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it is a parabola, as is the inverse, but in this case, each x in the domain (all real numbers) corresponds to exactly one member of the range
You can use the vertical line test
How so?
Oh ok
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