if an ellipitical whisperingn room has a height of 30 ft and a width of 100ft, where should two people stand if they would like to whisper back and forth and be hard.
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OpenStudy (turingtest):
So that basically is just asking what the foci of your ellipse are
OpenStudy (anonymous):
At the focii
OpenStudy (anonymous):
ok
OpenStudy (turingtest):
I forget the formula for the foci, let me look it up
OpenStudy (anonymous):
its A2-B2=C2
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OpenStudy (turingtest):
great, so what is the issue here?
OpenStudy (anonymous):
umm welll so would i do 100-30
OpenStudy (turingtest):
you understand that the formula is\[b^2-a^2=c^2\]so you have to square a and b...\[c=\sqrt{b^2-a^2}\]and the foci are\[(-c,0),(c,0)\]
OpenStudy (anonymous):
nooo its a^2-b^2=C^2
OpenStudy (anonymous):
depends on your major axis whether you add c to the x-coordinate of the center or y-coordinate
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OpenStudy (anonymous):
ohh ok
OpenStudy (anonymous):
ok so was i right when i said 100-30=70
OpenStudy (anonymous):
a^2 is not 100, b^2 is not 30
OpenStudy (anonymous):
they gave you the width and height of the ellipse, not a and b
OpenStudy (anonymous):
okkk so how do i find a and b thats my issue
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OpenStudy (anonymous):
They are half the width and height
OpenStudy (anonymous):
50-15
OpenStudy (anonymous):
i know that part
OpenStudy (anonymous):
so for horizontal major axis, a>b
a = 1/2 width
b= 1/2 height
OpenStudy (anonymous):
a=50
b=15
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
now c^2=a^2-b^2
OpenStudy (anonymous):
solve for c, the focii are at (c,0) and (-c,0)
OpenStudy (anonymous):
ok so 50^2-15^2
OpenStudy (anonymous):
\[c=\sqrt{50^2-15^2}\]
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OpenStudy (anonymous):
50^2=2500
15^2=225
2275 square root of that is 47.69
OpenStudy (anonymous):
\[5\sqrt{91} \approx 47.70\]
OpenStudy (anonymous):
ok same thing so since we know the foci so should people stand 47ft. away in order for them to whisper back and forth
OpenStudy (anonymous):
no, the focii are 47.7 ft from the center (0,0), so they'd stand twice as far away as 47.7, but be standing at the focii
OpenStudy (anonymous):
person a would be standing at (5sqrt(91),0), person b would be standing at
(-5sqrt(91),0)
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OpenStudy (anonymous):
ohh ok so do you think i would have to graph this
OpenStudy (anonymous):
|5sqrt(91)+5sqrt(91)|=10sqrt(91)
OpenStudy (anonymous):
does it tell you to graph it?
OpenStudy (anonymous):
i wouldn't
OpenStudy (anonymous):
ohh okay tynkss soo ,muchh
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