Mathematics
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OpenStudy (anonymous):
Need help with number 11, Please!
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OpenStudy (anonymous):
OpenStudy (anonymous):
what is 7 m supposed to be, the radius? i can't really see it
OpenStudy (anonymous):
yes, its the radius, and both angles are equal
OpenStudy (anonymous):
\[mEFG=\theta * \frac{\pi}{180}*r=160*\frac{\pi}{180}*7\]
OpenStudy (anonymous):
14pi circumference, arc length as ratio of theta to total circumference
(160/360)*14pi
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OpenStudy (anonymous):
ratio of theta to total angle of circle*
OpenStudy (anonymous):
how do i do 12
OpenStudy (anonymous):
mEHG=14pi-mEFG
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
hehe
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OpenStudy (anonymous):
that was surely wrong
OpenStudy (anonymous):
14pi=43.9 which rounds off to 44 right?
OpenStudy (anonymous):
Don't round the answers unless it says to
OpenStudy (anonymous):
For mEFG, write it as \[mEFG=\frac{56 \pi}{9}\]
OpenStudy (anonymous):
understand?
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OpenStudy (anonymous):
no.. im lost
OpenStudy (anonymous):
ok the circumference is 14pi
OpenStudy (anonymous):
C=2*pi*r=2*pi*7=14pi
OpenStudy (anonymous):
There are 360 degrees in a circle, and the measure of angle EDG is 160º
OpenStudy (anonymous):
so the measure of arc EFG is 160/360*14pi
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OpenStudy (anonymous):
simplifed this is 56pi/9
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
|dw:1330569659994:dw|
In the unit circle (radius of 1), the measure of an arc is the measure of theta in radians
OpenStudy (anonymous):
ok