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Mathematics 17 Online
OpenStudy (anonymous):

Need help with number 11, Please!

OpenStudy (anonymous):

OpenStudy (anonymous):

what is 7 m supposed to be, the radius? i can't really see it

OpenStudy (anonymous):

yes, its the radius, and both angles are equal

OpenStudy (anonymous):

\[mEFG=\theta * \frac{\pi}{180}*r=160*\frac{\pi}{180}*7\]

OpenStudy (anonymous):

14pi circumference, arc length as ratio of theta to total circumference (160/360)*14pi

OpenStudy (anonymous):

ratio of theta to total angle of circle*

OpenStudy (anonymous):

how do i do 12

OpenStudy (anonymous):

mEHG=14pi-mEFG

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

hehe

OpenStudy (anonymous):

that was surely wrong

OpenStudy (anonymous):

14pi=43.9 which rounds off to 44 right?

OpenStudy (anonymous):

Don't round the answers unless it says to

OpenStudy (anonymous):

For mEFG, write it as \[mEFG=\frac{56 \pi}{9}\]

OpenStudy (anonymous):

understand?

OpenStudy (anonymous):

no.. im lost

OpenStudy (anonymous):

ok the circumference is 14pi

OpenStudy (anonymous):

C=2*pi*r=2*pi*7=14pi

OpenStudy (anonymous):

There are 360 degrees in a circle, and the measure of angle EDG is 160º

OpenStudy (anonymous):

so the measure of arc EFG is 160/360*14pi

OpenStudy (anonymous):

simplifed this is 56pi/9

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

|dw:1330569659994:dw| In the unit circle (radius of 1), the measure of an arc is the measure of theta in radians

OpenStudy (anonymous):

ok

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