Question

Hey, Help me.. it is urgent . Iam stuck with the last part

Answer 1

???

Answer 2

pls help me

Answer 3

for 12-123:



First there is a confussion of notation where s is used for both the distance and the time.
example I suppose that the final velocity
v = (25 -0.15s) m/s, here I have assumed that the first s references the distance (i.e. 0.15s)

If that is correct then here is the solution:

Let a = acceleration.
x1 =0 (initial distance measuring from point A)
x2 = 51.5 M ( final distance travelled measured from point A)

v1 = 25 m/s ( initial velocity at point A)
v1 = [25 - (0.15*51.5)] ( final velocity after point A)

a = (v1-v0)(v1+v0)/[2(x1-x0)]
=(v1^2 - v0^2)/[2(x1-x0)] = 3.170625

Answer 4

therefore acceleration = 3.170625 m/s^2 ?