Question

Please solve (2-5y)/(y-10) + 1/(3y+2)

Answer 1

\[(2-5y+y-10)/(3y ^{2}-28y-20)\]
\[(-4y-8)/(3y ^{2}-28y-20)\]

Answer 2

How did you get that?

Answer 3

you must have a common denominator and that u have to multiply (y-10)*(3y+2) = 3x^2-28y-20.

the same thing with numerator multiply (2-5y)*(3y+2) and 1*(y-10)...

oopsss my numerator is wrong it should be (-15y^2+7y-16)

Answer 4

the answer is \[(-15y ^{2}+7y-16)/(3y ^{2}-28y-20)\]

Answer 5

OK, that makes more sense now.