Question

In the molecule, C2H4, what are the atomic
orbitals that participate in forming the sigma
bond between the C and H atoms

Answer 1

Ethene is an unsaturated hydracarbon, which is composed of two carbon and four hydrogen atoms. Its molecular formula is C2H4. The structural formula of ethene shows that each carbon contains two hydrogen and double bond is present two carbon atoms.
H2C = CH2
Each carbon atom of ethene is Sp2 hyberidized which contains three equivalent partially filled Sp2 hybrid orbitals and unhyberidized Pz orbital. The hybrid orbitals are arranged at the three corners of coplaner triangle with an angle of 120º.
Two Sp2 hybrid orbitals of carbon atoms overlapp with s atomic orbitals of hydrogen atoms to form a sigma bond between C - H due to the overlapping of Sp2 - S orbitals. The remaining Sp2 hybrid of each carbon atom overlapp with the Sp2 hybrid orbital of other carbon atom to form sigma bond between C - C due to the overlapping of Sp2 - Sp2.
The unhyberidized Pz orbital of each carbon atom are situated perpendicular to the Sp2 plane and parallel to the unhyberidized Pz orbitals of two different carbon atoms overlap side by side to form a pi bond between carbon atoms.
Diagram Coming Soon

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Answer 2

There is a sigma bond formed between a sp2 orbital from each Carbon atom, and a pi bond formed from a p orbital perpendicular to the plane of the molecule from each Carbon atom.

Answer 3

hope this helps :)

Answer 4

so h is sp2 and c is also sp2?

Answer 5

yes!