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Mathematics 18 Online
OpenStudy (amistre64):

Has anyone every actually tried reading Euclid Elements? I cant seem to get past making an equilateral triangle before I just want to fall asleep. This thing is a snooze-fest :/

OpenStudy (accessdenied):

i considered it ever since seeing khanacademy thing about geometry, but after trying to read newton's principia, im afraid to try. :(

OpenStudy (amistre64):

i cant believe theres X books at least.

OpenStudy (amistre64):

I know newton made a bunch of circles and arcs and lines and such ... oy!!

OpenStudy (amistre64):

nothing in here looks the least bit interesting tonight either :/

OpenStudy (accessdenied):

nope, ive resorted to reading my algebra 2 book and trying to figure out the error i saw earlier. D:

OpenStudy (amistre64):

i was gonna read hawkings "god created the integers" but it starts out with euclids elements lol ...ugh

OpenStudy (amistre64):

picked up a book on number theory and it starts with; this is how we divide ....

OpenStudy (amistre64):

identify the axis of symmetry when we give you x=2 as the axis of symmetry lol

OpenStudy (amistre64):

it takes longer to type these "give me the answer" questions in than it does to solve them ....

OpenStudy (accessdenied):

heh, yeah... there was somebody earlier who seemed to just be posting their entire hw assignment up, and im pretty sure it was just linear equations. :p

OpenStudy (amistre64):

yeah, i used to call that the homework hour. post your stuff; go play some video games, come back and write up all the answers ....

OpenStudy (amistre64):

find the inverse of a linear equation ....

OpenStudy (accessdenied):

"You can solve an equation of the form x^(n/m) = k by raising each side of the equation to the power n/m..." I think the book is lying to me. :(

OpenStudy (amistre64):

burn it on the bonfire; thatll teach it a lesson ;)

OpenStudy (amistre64):

since cross products are not commutable; the product rule application on a cross product is very specific. D[axb] = a'xb+axb' teacher had it as a'xb+b'xa :)

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