Question

solve 7^x<=1?

Answer 1

x<0

Answer 2

how do you get that?

Answer 3

\[\large a^x\le y\iff x\le \log_a y\]

Answer 4

in your case we have\[7^x\le1\]taking the log base seven of both sides we get\[x=\log_71\]and log base anything of 1 is zero, because any number besides zero to the power of zero equals 1\[\log_a0=1\iff a^0=1;x\neq0\]

Answer 5

sorry, typo\[x\le\log_71=0\]

Answer 6

ty

Answer 7

oh wait terrible typo in the last line, should be\[\log_a1=0\iff a^0=1;x\neq0\]it is important to know that\[\log_a0\]is undefined