Question

the derivative of y=x^(2x+1)?

Answer 1

y=x^(2x+1)

Ly= Lx^(2x+1)

Ly= (2x+1)Lx

1/y= 2Lx+(2x+1)/x

Answer 2

the answer is x^(2x+1)*(2lnx+2+1/x) but i can't figure out where the term 2 in the parenthesis came from

Answer 3

forgot my y' :)

1/y y'= 2Lx+(2x+1)/x

y'= y(2Lx+(2x+1)/x)

Answer 4

ooops

Answer 5

log it all, the derivae it with logs and product rules

Answer 6

oh. so by taking the ln of both sides....i can solve it?

Answer 7

yep

Answer 8

just know that ln(y) ' = 1/y y'

Answer 9

thank you!!

Answer 10

yer welcome

Answer 11

Ok.