Question

Find the 20th term of (x+3)^22.

Answer 1

I'd like to also know the process of getting the answer :)

Answer 2

do you have an idea on how to solve it? any advice would help c:

Answer 3

Formula for the k+1 term is \[\left(\begin{matrix}n\\ k\end{matrix}\right)a ^{n-k}b ^{k}=\left(\begin{matrix}22 \\19\end{matrix}\right)x ^{3}5^{19}\]

Answer 4

Wait wait, so I solve that?

Answer 5

Well, what you really need to do is simplify....

Answer 6

Simplify... how?

Answer 7

Calculate \[\left(\begin{matrix}22 \\ 19\end{matrix}\right)=22!/(19!3!)\] then calculate \[5^{19}\] and multiply. You'll get (REALLY BIG NUMBER)x^5.