Question

find the derivative of y = 3t^6ln(2t)

Answer 1

you'll need to use the product rule, [f(x)*g(x)]' = f'(x)g(x) + g'(x)f(x). you'll also need to know the chain rule [f(g(x))]' = f'(g(x))*g'(x), and the derivative of 1n(x) is by definition 1/x

Answer 2

yea i know but my homework keeps saying what i do is wrong i got 18t^6ln(2t)+3t^5/2

Answer 3

Try 3 t^5 (1+6 log(2 t))