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find the derivative of y = 3t^6ln(2t)
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you'll need to use the product rule, [f(x)*g(x)]' = f'(x)g(x) + g'(x)f(x). you'll also need to know the chain rule [f(g(x))]' = f'(g(x))*g'(x), and the derivative of 1n(x) is by definition 1/x
yea i know but my homework keeps saying what i do is wrong i got 18t^6ln(2t)+3t^5/2
Try 3 t^5 (1+6 log(2 t))
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