quadractic equation: x^2/3+2x=-2 can anyone verify my answer of x=-2+-i square root 2 is correct
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OpenStudy (anonymous):
you can verify that, armed with the definition i^2 = -1, you get (1/3)(2 + i)^2 + 2(2 + i) + 2, if this equals 0 you're correct.
OpenStudy (anonymous):
ok. can you work the problem
OpenStudy (anonymous):
\[\frac{x^2}{3}+2x=-2\], this your question?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[\frac{x^2+3(2x)}{3}=-2\]
\[x^2+6x=-6\]
\[x^2+6x+6=0\]
From this point, we can see your answers are wrong because the discrimant is positive, meaning the quadratic has real number solutions
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OpenStudy (anonymous):
bummer
OpenStudy (anonymous):
I will rework it.
OpenStudy (anonymous):
alright i'll let you know if you get the right answer
OpenStudy (anonymous):
since when is 6^2 - 4(6) <0 ? it's 36 - 24 = 12. positive discriminant, so your complex answer 2 - i cannot be correct.
OpenStudy (anonymous):
my answer is \[x=-3 \pm 3\sqrt{2}\]
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OpenStudy (anonymous):
not quite
OpenStudy (anonymous):
try 1 more time?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
looks like you messed up evaluating the sqrt(12)
OpenStudy (anonymous):
\[-3 \pm 2\sqrt{3?}\]
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OpenStudy (anonymous):
nope, want me to write the equation?
OpenStudy (anonymous):
or \[-3 \pm \sqrt{3}\]
OpenStudy (anonymous):
that ones right
OpenStudy (anonymous):
okay the 2 does cancel. thanks this has been very helpful