Question

quadractic equation: x^2/3+2x=-2 can anyone verify my answer of x=-2+-i square root 2 is correct

Answer 1

you can verify that, armed with the definition i^2 = -1, you get (1/3)(2 + i)^2 + 2(2 + i) + 2, if this equals 0 you're correct.

Answer 2

ok. can you work the problem

Answer 3

\[\frac{x^2}{3}+2x=-2\], this your question?

Answer 4

yes

Answer 5

\[\frac{x^2+3(2x)}{3}=-2\]
\[x^2+6x=-6\]
\[x^2+6x+6=0\]
From this point, we can see your answers are wrong because the discrimant is positive, meaning the quadratic has real number solutions

Answer 6

bummer

Answer 7

I will rework it.

Answer 8

alright i'll let you know if you get the right answer

Answer 9

since when is 6^2 - 4(6) <0 ? it's 36 - 24 = 12. positive discriminant, so your complex answer 2 - i cannot be correct.

Answer 10

my answer is \[x=-3 \pm 3\sqrt{2}\]

Answer 11

not quite

Answer 12

try 1 more time?

Answer 13

k

Answer 14

looks like you messed up evaluating the sqrt(12)

Answer 15

\[-3 \pm 2\sqrt{3?}\]

Answer 16

nope, want me to write the equation?

Answer 17

or \[-3 \pm \sqrt{3}\]

Answer 18

that ones right

Answer 19

okay the 2 does cancel. thanks this has been very helpful

Answer 20

yw