1 C8H9NO3 - 4 C8H10NO3

to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?

Question

1 C8H9NO3 -> 4 C8H10NO3

to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?

anonymous · Answer

I'm half asleep I know this but I just need to confirm so I can finish my lab

anonymous · Answer

so if I had 

0.00309mol of reactant I would have 0.01236moles of product therefore I would have 2.1g of product?

anonymous · Answer

167g/mol is the molecular mass of the product

sasogeek · Answer

I'm not good at this but logically that makes sense

anonymous · Answer

I'm a pro at stochiometry but is 4 in the morning lol

anonymous · Answer

so im not a pro at the momment

sasogeek · Answer

lol k

anonymous · Answer

thanks :) wow I didnt get much of yield at all ugh

sasogeek · Answer

yw :)