Question

1 C8H9NO3 -> 4 C8H10NO3

to convert the moles of the reactant I would just multiply the moles of it by 4 and then multiply the moles by the molecular weight of C8H10NO3 right?

Answer 1

I'm half asleep I know this but I just need to confirm so I can finish my lab

Answer 2

so if I had

0.00309mol of reactant I would have 0.01236moles of product therefore I would have 2.1g of product?

Answer 3

167g/mol is the molecular mass of the product

Answer 4

I'm not good at this but logically that makes sense

Answer 5

I'm a pro at stochiometry but is 4 in the morning lol

Answer 6

so im not a pro at the momment

Answer 7

lol k

Answer 8

thanks :) wow I didnt get much of yield at all ugh

Answer 9

yw :)