Question

9x^2+x=5 this is the quadtratic formula: can someone help get is set up to solve

Answer 1

9x^2+x-5=0

Answer 2

and use the quadratic equation

Answer 3

ax^2 + bx + c = 0

Answer 4

so the a= b=1 c=5?

Answer 5

a=9?

Answer 6

c=-5

Answer 7

x=( -b +or - sqrt( b^2 - 4 * a *c))/2*a

Answer 8

Yes

Answer 9

But c=-5

Answer 10

ok.

Answer 11

Since quadratic equation should be of the form ax^2+bx+c

Answer 12

the plus or minus means you have to do the equation twice one with + and one with - which means you should have two answers for x

Answer 13

ax^2 + bx + c = 0
so \[x=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]

Answer 14

thanks.

Answer 15

amir looks better follow that one

Answer 16

yes.

Answer 17

i was makin that equation and it take a while if it didn't i'll answer first

Answer 18

amir.sat will you verify my answer is correct once i work the problem?

Answer 19

where's you answer?

Answer 20

\[-1\pm \sqrt{9 /18}\]

Answer 21

or does the 9/18 reduce futher

Answer 22

what's this?
is it the solve way of that problem?

Answer 23

replace the value in the formula that i've posted.

Answer 24

a=9 b=1 c=-5? right I just plug in the numbers

Answer 25

so you are able to find the values of x

Answer 26

what is your answer? please

Answer 27

ok wait

Answer 28

\[x=\frac{-1+\sqrt{1+1800}}{18}\]
\[x=\frac{-1-\sqrt{1+1800}}{18}\]

Answer 29

-4ac= -4(9)(-5) = 180?

Answer 30

not sure where you got 1800

Answer 31

yes okk it's 180

Answer 32

and the square root of 180 =\[6\sqrt{5}\]

Answer 33

no it's 180+1

Answer 34

okay then it's 9/18

Answer 35

it's not