f(x)=(x^2)(e^5x)
find f"(x).

Question

f(x)=(x^2)(e^5x)
find f"(x).

hoblos · Answer

f(x) = u(x) v(x)
f'(x) = u'(x)v(x) + u(x)v'(x)
use this formula to get the answer

anonymous · Answer

o trust me we have tried lol

anonymous · Answer

you will have to use the quotient rule and that's what hobios has shown....

anonymous · Answer

anonymous · Answer

whoops product rule!!!

hoblos · Answer

f'(x) = (2x)(e^5x) + 5(x^2)(e^5x)
f''(x) = 2e^5x + 10x(e^5x) + 10x(e^5x) + 25(x^2)(e^5x)

anonymous · Answer

I just did it I dodn't have any big issues. Just use the produle rule 1 time for the f'(x) and twice for the f''(x)...shouldn't be nothing tricky

anonymous · Answer

just remember the derivative of e^x = e^x * x'

hoblos · Answer

f''(x) = (e^5x)(2+20x + 25x^2)

anonymous · Answer

yup thats it. thanks.

hoblos · Answer

its my pleasure XD

anonymous · Answer

can you show me how you got f''(x) = 2e^5x + 10x(e^5x) + 10x(e^5x) + 25(x^2)(e^5x)

anonymous · Answer

i know u used the product rule but i dont see it

hoblos · Answer

use product rule for each part alone then add them
[(2x)(e^5x)]'  = 2e^5x + 10x(e^5x)
[5(x^2)(e^5x)]' = 10x(e^5x) + 25(x^2)(e^5x)

anonymous · Answer