Question

will give medals to anyone who tries! Find the altitude of an isosceles triangle with a vertex angle of 70° and a base of 246.
Write answer to nearest tenth.

Answer 1

here is the correct answer for you
tan(35) = 123/x
x = 123tan(35)


x = 123 * 0.7 = 86.1

Answer 2

Since the altitude of isosceles triangle will divide both vertex angle and base in half
=> Altitude = half base/ tan 35° = 175.7