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Mathematics 20 Online
OpenStudy (anonymous):

d(x^x)/dx

OpenStudy (anonymous):

And why? Also, what is d(x^x^x)/dx, if it will not be immediately obvious from the main question's answer.

OpenStudy (jamesj):

writing y = x^x, we have ln y = x . ln x Now differentiate both sides wrt x

OpenStudy (anonymous):

Surely that just gives us d(lny)/dx?

OpenStudy (anonymous):

ln y = x lnx differentiate both sides dy/dx * 1/y = x * 1/x + ln x dy/dx = ( 1 + lnx ) / 1/y = y(1 + lnx) = x^x ( 1 + ln x)

OpenStudy (anonymous):

i would write \[x^x=e^{x\ln(x)}\] and use the chain and product rule. you will get the same thing, since all the work is in the product rule

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