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d(x^x)/dx
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And why? Also, what is d(x^x^x)/dx, if it will not be immediately obvious from the main question's answer.
writing y = x^x, we have ln y = x . ln x Now differentiate both sides wrt x
Surely that just gives us d(lny)/dx?
ln y = x lnx differentiate both sides dy/dx * 1/y = x * 1/x + ln x dy/dx = ( 1 + lnx ) / 1/y = y(1 + lnx) = x^x ( 1 + ln x)
i would write \[x^x=e^{x\ln(x)}\] and use the chain and product rule. you will get the same thing, since all the work is in the product rule
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