calculate g'(x) where g(x) is the inverse of f(x) f(x)=x^(-4)
my answer was (-x^(-5/5))/4 but it was wrong
(-1/4)y^(-5/4) if x is not equal to 0
replace y by x in my answer
ok what?? I followed the books example and that is what I got.
dont know how you got that answer!!!
you said your answer is wrong :)
an inverse means you can undo the process
I followed the steps in cramster and thats what I got.
oh, you used cramster, thats different
i got no idea what they step it as
well its wrong regardless so can you show me step by step please?
calculate g'(x) where g(x) is the inverse of f(x) f(x)=x^(-4) [f(x)]^(-1) = x^4 4rt [f(x)]^(-1) = x
simply undo the function by solving for "x"
y = 3x , whats our inverse? y/3 = x
y = x^(-4) (y = x^(-4) )^(-1/4) y^(-1/4) = x
just assume y=f(x) then solve the equation for x=g(y) then interchange y and x, i.e., y=g(x) g(x) is the inverse
?
solve for x ...
then derive
Inverse of f(x)=x^(-4) is g(x)= +/- x^(-1/4) on x>0. Derivative is g'(x) = +/- (1/4)x^(-5/4) on x>0.
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